int* when in a function parameter list (I left out the optional names). Additionally, an array name decays to a pointer to the first element when passed to a function (and not passed by reference) so both int …

Oct 16, 2013 · So the called function sees a pointer to the array (passed by reference) and operates on it. If you want to make a copy, you have to either do so explicitly, or put your array inside a struct …

An array passed to a function is converted to a pointer. When you pass a pointer as argument to a function, you simply give the address of the variable in the memory.

May 18, 2010 · 148 Why don't you pass the entire array and process it as needed inside the function?

Jul 4, 2011 · I wrote a function containing array as argument, and call it by passing value of array as follows.

Because the array is being passed by value, an exact copy of the array is made and placed on the stack. The called function then receives this copy of the array and can print it. Because the array …

C does not really have multi-dimensional arrays, but there are several ways to simulate them. The way to pass such arrays to a function depends on the way used to simulate the multiple dimensions: 1) …

Aug 6, 2012 · When you pass an array as a parameter to a function it decays to a pointer to the first element of the array. So there is normally never a need to pass a pointer to an array.

The name of an array variable, is a valid expression whose value is a pointer the the first member of the array. If you have some function foo(T* t), and you have an array T a[N]; then when you write foo(a); …

In C language, 2D array is just an array of arrays. Because of that, you should pass the function a pointer to the first sub-array in the 2D array. So, the natural way, is to say int (*p)[numCols] (that …