Jul 28, 2010 · 149 There is, in fact, a general formula for solving quartic (4th degree polynomial) equations. As the cubic formula is significantly more complex than the quadratic formula, the quartic …

Remark: There is a formula for the roots of a general quartic, due originally to Ferrari. A number of other mathematicians, including Descartes, produced variants.

Jan 25, 2021 · And how the same method could be used to solve the following function: If not the same method used by Peđa Terzić, how else could you approach to solving a quartic function?

6 What about a set of expressions in the quartic's coefficients that discriminate between all cases? There are 9 cases: 4 distinct real roots. 3 distinct real roots with one of them being a double root. 2 …

May 1, 2020 · I am trying to find the equation of a quartic function given its three turning points. Here is the information I have: maximum turning points at $(-12, 1)$ and $(-6,1)$; minimum turning point at $(...

Sep 15, 2019 · My teacher gave a function of $$f(x)= 2x^4-3x^3-21x^2+16x+60$$ He said that there needs to be $4$ turning points. I only now how to find the turning points if the ...

Oct 21, 2013 · How to get the roots of a quartic function when given a quadratic factor Ask Question Asked 12 years ago Modified 8 years, 11 months ago

May 10, 2016 · For a quartic function, setting the first order derivative equal to zero should give us the local extrema. Since the first derivative is a cubic function, which can have three real roots, shouldn't …

Aug 8, 2016 · 0 Because the leading term has an even power, a quartic polynomial starts decreasing and ends increasing, or conversely. So there is no room for an even number of extrema. The …

Jan 3, 2017 · A quartic is never irreducible over real polynomials. It always has at least one factorization into two quadratic factors. Finding those factors is the tricky part.